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Journal of Multidisciplinary Engineering Science and Technology JMEST. ISSN 2458 9403,Vol 3 Issue 3 March 2016,1 Rivet Design Analysis. to be embedded in the clinched joint and then, compressing the protruded part of the pin using a The rivet design comprises the following. single stroke under a flat pair of dies The optimization elements diameter of the rivet number of rivets pitch. result on this reshaping process established that the of the rivet and thickness of the cover plate And. protrusion height of riveted joints should be 1 0mm these are as calculated as follows. while the average cross tension and tension shearing. strengths were increased to 1154 9N and 2757 3N as i Diameter of rivet. against 957 9 and 1229 4N respectively, The diameter of the rivet in mm is obtained by the. The riveting process mathematics modeling and, simulating to more accurately analyze deformation of relation. thin walled sheet metal parts was discussed by 6 6 1. Their proposition was based on the theory of, ABAQUS finite element system mathematics and Where t is the thickness of the main plate in mm.

mechanics models for the elastic deformation plastic. deformation and spring back of the rivet pins And ii Number of rivets. their findings based on comparison of the three The number of rivets is usually calculated when. theories proved to be true from the modeling the length of the joint is small But when the joint is a. perspective, continuous one as in case of boilers the number of. Reference 7 8 and 9 studied the quality of drilled. and milled rivet holes in carbon fiber reinforced rivets is not calculated In a small joint the number of. plastics vibration measurements of clinched joints rivets is given as. and self pierce riveting and hybrid joining of boron. steels in multi material and multi sheet joints,respectively Their contributions were on the. Where P is the thickness of the main plate in mm, applications of riveting joints for quality output in. carbon fiber reinforced plastics and boron steels is least rivet value for shearing and bearing. Despite the enormous work carried out by some of the iii Pitch of rivet. aforementioned authors there had not been any, research work focusing on the rivet joints design aided The pitch should be between 2 5 to 4 times the. by the use of dedicated software Therefore this paper diameter of the rivet from practical considerations the. focuses on the design of rivet joint tailored towards pitch should not be less than 2d 12mm where d is. teaching aid assistance for the learning of the design the diameter of the rivet in mm a little consideration. in fastening operations will show that the strength of the joint in such a case. II METHODOLOGY will be tearing strength of the plate that is Pt because. the value of Pt is taken lesser than the rivet values in. The methods adopted for the work is simply by, considering the design equations has laid out in texts shearing and tearing.

transform the various design steps into flowchart,Efficiency 3. algorithm required for the development of the P, software and then translate the algorithm into coding. iv Thickness of cover plate,using the visual basic 6 0 programming language. Therefore the subsequent sections of this paper shall The two cover plates are provided each of. be considered as spelt out in the aforementioned thickness 0 625t where t is the thickness of the main. A Design Equations plate in mm 1, The design of riveted joint is an important job in 2 Rivet Joint Design Analysis. modern design in the present age A faulty design can The rivet joint is designed for using the following. lead to many complications while designing a riveted parameters. joint for structural use the following assumptions must. be put in place load on joints is equally sheared by all i Tension failure mode. the rivets plates are rigid bearing stress is uniform 4. shearing stress in all the rivets is uniform the bending. of rivet is neglected initial tensile stress or shearing ii Bearing failure mode. stress in the rivet is neglected and frictional forces 5. between the plates are neglected,iii Shearing failure mode.

www jmest org,JMESTN42351477 4371, Journal of Multidisciplinary Engineering Science and Technology JMEST. ISSN 2458 9403,Vol 3 Issue 3 March 2016, Where n is number of rivets P is allowance load w is 16. main plate width t is plate thickness d is nominal rivet. Where s is the number of sections s 1 2 3, diameter D is diameter of the hole on the plate D d. some clearance 3 are permissible tensile, bearing and shearing stresses respectively The xii Strength of the main plate this is the value of. shearing pressure Ps bearing pressure and plate at a section where the value is minimum. strength design calculation is as listed in equations plus the preceding strength of rivet. 7 8 and 9 Minimum nr X strength of one rivet,Where nr is the number of rivets preceding the.

xiii Tearing of cover plate, iv Diameter of rivets d is still same with that of. equation 1 6,Where b is width of plate Sn is section. Where t is thickness of the main plate in mm d must. number Pts is minimum and tc is cover,be greater than t. v Number of rivets B Flowchart Algorithm for Rivet Design Software. This is considered when the length of the joint The algorithm of the design is as stated in Fig 1 to. is small Fig 4,the lesser value is used,vi Pitch of rivets 2d 12mm 11. vii Joint Efficiency,least of Ps Pb and Pt,Where P is thickness of the main plate in.

mm Rv is rivet value that is the least of the,rivet values for shearing and bearing. pressure is permissible stress in tearing t,is thickness of the plate d is diameter of rivet. and P is pitch,viii Plate thickness ts 0 625t 13,ix Shearing of rivet. Where is number of rivet joint type if,single then 1 if double then 2 if. multiple then is permissible shear,stress in rivets d is diameter of rivets.

x Bearing strength of rivets,It should be noted that If Pb Ps the strength. of the rivet else strength of the rivet,xi Tearing of the main plate. www jmest org,JMESTN42351477 4372, Journal of Multidisciplinary Engineering Science and Technology JMEST. ISSN 2458 9403,Vol 3 Issue 3 March 2016, Fig 1 Flowchart depicting the algorithm for rivets joint design. www jmest org,JMESTN42351477 4373, Journal of Multidisciplinary Engineering Science and Technology JMEST.

ISSN 2458 9403,Vol 3 Issue 3 March 2016,Fig 2 Continuation of Fig 1. www jmest org,JMESTN42351477 4374, Journal of Multidisciplinary Engineering Science and Technology JMEST. ISSN 2458 9403,Vol 3 Issue 3 March 2016,1 2 Is it a. 1 3 section,If 11 11 111,If 11 111 111 1,11 1 11 111 Else 11 1 11 111. 11 1 111 1,11 1 1 1 1 11,If 11 1 11 11,11 111 1 11.

Fig 3 Continuation of Fig 2,www jmest org,JMESTN42351477 4375. Journal of Multidisciplinary Engineering Science and Technology JMEST. ISSN 2458 9403,Vol 3 Issue 3 March 2016,Fig 4 Continuation of Fig 3. www jmest org,JMESTN42351477 4376, Journal of Multidisciplinary Engineering Science and Technology JMEST. ISSN 2458 9403,Vol 3 Issue 3 March 2016,C Software Development. The flowchart of Fig 1 to Fig 4 is coded using visual. basic 6 0 programming approach The built up or,deployed programs resulting from these are as.

discussed in Fig 5 to Fig 9 Fig 5 displays the main. menu of the system,Fig 7 Lap joint submenu interface. Once any type of the lap joint is clicked it displays the. input parameters design templates This is as shown. in the displayed template of Fig 8 While Fig 9 shows. the output template of the developed software,Fig 5 Application main menus. While Fig 6 gives graphical user interface that,provides shortcut to the major components and. functions of the software package it is accompanied. with good navigation technique, On accessing the type of joint as displayed in Fig 6. will display the submenu interface for lap joints as. shown in Fig 7,Fig 8 Lap joint input menu interface.

III DEVELOPED SOFTWARE TESTING AND EVALUATION,Performance test of the developed software was. carried out using two case studies of manually solved. calculation from Machine design textbook by 1 and,the resulting answers from the developed software. Fig 6 Type of rivet joint,were compared with the values obtained from the. aforementioned text,A Case Study One,A double riveted lap joint is made between 15mm. thick plates The rivet diameter and the pitch are, 25mm and 75mm respectively If the ultimate stresses.

are 400MPa in tension 320MPa in shear and 640MPa, in crushing find the minimum force per pitch which. www jmest org,JMESTN42351477 4377, Journal of Multidisciplinary Engineering Science and Technology JMEST. ISSN 2458 9403,Vol 3 Issue 3 March 2016, will rupture bent If the above joint is subjected to a 7500 2. load such that the factor of safely is 4 find out the. actual stresses developed in the plates and rivets 1 7500 2 252. Manual Solution Approach,Given t 15mm d 225mm p 75mm and. And actual crushing resistance of the rivets Psa,400mpa 400N mm2 320MPa 320 75000.

N mm2 640MPa 640 N mm2 2 25 15 750, To calculate the minimum force per pitch which will. Software solution to Case study 1,rupture the joint. The given data were input into the developed system. Since the ultimate stresses are given therefore there. as picked from case study sample problem 1 and the. is need to find the ultimate values of the resistances of. resulting solution is as shown in Fig 9, The ultimate tearing resistances of the plate per pitch. 75 25 15 400 300000, The ultimate shearing resistance of the rivet per pitch. is thus calculated as,2 252 320 314200, And the ultimate crushing resistance of the rivets per.

pitch is derived as,2 25 15 640 480000, The minimum force per pitch which will rupture the. joint is 300000N or 300KN 1,Actual stresses produced in the plates and rivets. Since factor of safety is 4 therefore a safe load per Fig 9 Software solution to case study 1. pitch length of the joint is thus calculated to be. 300000 75000,4 B Case Study Two,If and be the actual tearing shearing. and crushing stresses produced respectively with a Find the efficiency of the following riveted joints. safe load of 75 000N in tearing shearing and i Single riveted lap joint of 6mm plates with. 20mm diameter rivets having a pitch of, crushing then the actual tearing resistance of the 50mm. plates Pta will be ii Double riveted lap joint of 6mm plates with. 20mm diameter rivets having a pitch of,75000 65mm,75 25 15 750 Assuming the given following values.

Permissible tensile stress in plate 120MPa, 750 7500 Permissible shearing stress in rivets 90MPa and. 100 Permissible crushing stress in rivets 180MPa 1. Actual shearing resistance of the rivets Psa is thus. calculated as,www jmest org,JMESTN42351477 4378, Journal of Multidisciplinary Engineering Science and Technology JMEST. ISSN 2458 9403,Vol 3 Issue 3 March 2016,Manual Solution Approach. Given t 6mm d 20mm 120Mpa,120N mm2 90Mpa 90N mm2 180. i Efficiency of the first joint,Given pitch P 50mm.

There is need to find the tearing resistance of the. plate shearing and crushing resistance of the rivets. a Tearing resistance of the plate, The tearing resistance of the plate per pitch length. 50 20 6 120 21600,b Shearing resistance of the rivet. Since the joint is a single riveted lap joint, therefore the strength of one rivet in single shear is. taken Therefore the shearing resistance of one rivet. 202 90 28278,c Crushing resistance of the rivet,Since the joint is a single riveted therefore. strength of one rivet is taken And crushing resistance. of one rivet Fig 10 Software solution to case study 2a. ii Efficiency of the second joint,20 6 180 21600,a Tearing resistance of the joint.

Strength of the joint least Pt Ps and Pc 21600N The tearing resistance of the plate. Then strength of the unriveted solid plate,65 20 6 120 32400. 50 60 120 36000,b Shearing resistance of the rivets. Efficiency of the joint, N least of Since the joint is double riveted lap joint therefore. strength of two rivets in single shear is taken,Knowing that shearing resistance of the rivets is. 2 202 90 56556, Software solution to Case study 2a c Crushing resistance of the rivet.

Since the joint is double riveted therefore strength. The given data were input into the developed of two rivets is taken Knowing that crush. system as picked from case study sample problem 2a resistance of rivets. and the resulting solution is as shown in Fig 10,20 20 6 43200. Therefore strength of the joint least of Pt Ps,and Pc 32400N. But strength of the unriveted or solid plate,65 6 120 46800. Efficiency of the joint,www jmest org,JMESTN42351477 4379. Journal of Multidisciplinary Engineering Science and Technology JMEST. ISSN 2458 9403,Vol 3 Issue 3 March 2016,model of the expected type of rivet Finally the.

software is user friendly and interactive,ACKNOWLEDGMENT. The author sincerely appreciated Mr Yusuf, Hassan a research student who did the compilation of. Software solution to Case study 2b the script Also the members of Advanced. 6 0 in designing for riveted joint of various types The various design equations for rivet joints design and calculations were put together and sorted in classifying the input and output parameters for the coding aspect of the work The software is flexible enough to accommodate

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